1/3f+5=10

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Solution for 1/3f+5=10 equation: 



1/3f+5=10

We move all terms to the left:

1/3f+5-(10)=0



Domain of the equation: 3f!=0

f!=0/3

f!=0

f∈R



We add all the numbers together, and all the variables

1/3f-5=0

We multiply all the terms by the denominator


-5*3f+1=0

Wy multiply elements

-15f+1=0

We move all terms containing f to the left, all other terms to the right

-15f=-1

f=-1/-15

f=1/15

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