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1/3h-4(2/3h-3)=2/3(h-9)
We move all terms to the left:
1/3h-4(2/3h-3)-(2/3(h-9))=0
Domain of the equation: 3h!=0
h!=0/3
h!=0
h∈R
Domain of the equation: 3h-3)!=0
h∈R
Domain of the equation: 3(h-9))!=0We multiply parentheses
h∈R
1/3h-8h-(2/3(h-9))+12=0
We calculate fractions
-8h+(3hh/(9h^2h+(-(2*3h)/(9h^2h+12=0
We can not solve this equation
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