1/3h-4(2/3k-3)=2/3k-6

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Solution for 1/3h-4(2/3k-3)=2/3k-6 equation: 


x in (-oo:+oo)

(1/3)*h-(4*((2/3)*k-3)) = (2/3)*k-6 // - (2/3)*k-6

(1/3)*h-(4*((2/3)*k-3))-((2/3)*k)+6 = 0

(1/3)*h-4*((2/3)*k-3)+(-2/3)*k+6 = 0

h/3-4*(2/3*k-3)+(-2*k)/3+6 = 0

(-4*3*(2/3*k-3))/3+h/3+(-2*k)/3+(3*6)/3 = 0

h-4*3*(2/3*k-3)-2*k+3*6 = 0

h-8*k-2*k+18+36 = 0

h-10*k+18+36 = 0

h-10*k+54 = 0

(h-10*k+54)/3 = 0

(h-10*k+54)/3 = 0 // * 3

h-10*k+54 = 0

x belongs to the empty set

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