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1/3k+1/5k=1
We move all terms to the left:
1/3k+1/5k-(1)=0
Domain of the equation: 3k!=0
k!=0/3
k!=0
k∈R
Domain of the equation: 5k!=0We calculate fractions
k!=0/5
k!=0
k∈R
5k/15k^2+3k/15k^2-1=0
We multiply all the terms by the denominator
5k+3k-1*15k^2=0
We add all the numbers together, and all the variables
8k-1*15k^2=0
Wy multiply elements
-15k^2+8k=0
a = -15; b = 8; c = 0;
Δ = b2-4ac
Δ = 82-4·(-15)·0
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-8}{2*-15}=\frac{-16}{-30} =8/15 $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+8}{2*-15}=\frac{0}{-30} =0 $
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