1/3k-(k+1/3)=1/9(k+1)

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Solution for 1/3k-(k+1/3)=1/9(k+1) equation: 


k in (-oo:+oo)

(1/3)*k-k-(1/3) = (1/9)*(k+1) // - (1/9)*(k+1)

(1/3)*k-((1/9)*(k+1))-k-(1/3) = 0

(-1/9)*(k+1)+(1/3)*k-k-1/3 = 0

k/3-1/9*(k+1)-k-1/3 = 0

(-1/9*3*(k+1))/3+k/3+(3*(-k))/3-1/3 = 0

k-1/9*3*(k+1)+3*(-k)-1 = 0

2/3*k-3*k-1-1/3 = 0

-7/3*k-1-1/3 = 0

-7/3*k-4/3 = 0

(-7/3*k-4/3)/3 = 0

(-7/3*k-4/3)/3 = 0 // * 3

-7/3*k-4/3 = 0

-7/3*k-4/3 = 0 // + 4/3

-7/3*k = 4/3 // : -7/3

k = 4/3/(-7/3)

k = -4/7

k = -4/7

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