1/3k-(k+1/3)=1/9(k+3)

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Solution for 1/3k-(k+1/3)=1/9(k+3) equation:


k in (-oo:+oo)

(1/3)*k-k-(1/3) = (1/9)*(k+3) // - (1/9)*(k+3)

(1/3)*k-((1/9)*(k+3))-k-(1/3) = 0

(-1/9)*(k+3)+(1/3)*k-k-1/3 = 0

k/3-1/9*(k+3)-k-1/3 = 0

(-1/9*3*(k+3))/3+k/3+(3*(-k))/3-1/3 = 0

k-1/9*3*(k+3)+3*(-k)-1 = 0

2/3*k-3*k-1-1 = 0

-7/3*k-1-1 = 0

-7/3*k-2 = 0

(-7/3*k-2)/3 = 0

(-7/3*k-2)/3 = 0 // * 3

-7/3*k-2 = 0

-7/3*k-2 = 0 // + 2

-7/3*k = 2 // : -7/3

k = 2/(-7/3)

k = -6/7

k = -6/7

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