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1/3k-(k+1/3)=1/9(k=3)
We move all terms to the left:
1/3k-(k+1/3)-(1/9(k)=0
Domain of the equation: 3k!=0
k!=0/3
k!=0
k∈R
Domain of the equation: 9k!=0We add all the numbers together, and all the variables
k!=0/9
k!=0
k∈R
1/3k-(+k+1/3)-(1/9k=0
We get rid of parentheses
1/3k-k-(1/9k-1/3=0
We can not solve this equation
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