1/3k-(k+1/4)=1/12(k+3)

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Solution for 1/3k-(k+1/4)=1/12(k+3) equation: 



1/3k-(k+1/4)=1/12(k+3)

We move all terms to the left:

1/3k-(k+1/4)-(1/12(k+3))=0



Domain of the equation: 3k!=0

k!=0/3

k!=0

k∈R





Domain of the equation: 12(k+3))!=0

k∈R



We add all the numbers together, and all the variables

1/3k-(+k+1/4)-(1/12(k+3))=0

We get rid of parentheses

1/3k-k-(1/12(k+3))-1/4=0

We calculate fractions


(48kk/(144k^2k+(-(1*3k*4)/(144k^2k+(-36k^2)/(144k^2k-k=0

We can not solve this equation

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