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1/3k-5=2/3k+6
We move all terms to the left:
1/3k-5-(2/3k+6)=0
Domain of the equation: 3k!=0
k!=0/3
k!=0
k∈R
Domain of the equation: 3k+6)!=0We get rid of parentheses
k∈R
1/3k-2/3k-6-5=0
We multiply all the terms by the denominator
-6*3k-5*3k+1-2=0
We add all the numbers together, and all the variables
-6*3k-5*3k-1=0
Wy multiply elements
-18k-15k-1=0
We add all the numbers together, and all the variables
-33k-1=0
We move all terms containing k to the left, all other terms to the right
-33k=1
k=1/-33
k=-1/33
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