1/3k=1+1/k

Solution for 1/3k=1+1/k equation:

D( k )

k = 0

k = 0

k = 0

k in (-oo:0) U (0:+oo)

(1/3)*k = 1/k+1 // - 1/k+1

(1/3)*k-(1/k)-1 = 0

(1/3)*k-k^-1-1 = 0

1/3*k^1-1*k^-1-1*k^0 = 0

(1/3*k^2-1*k^1-1*k^0)/(k^1) = 0 // * k^2

k^1*(1/3*k^2-1*k^1-1*k^0) = 0

k^1

(1/3)*k^2-k-1 = 0

(1/3)*k^2-k-1 = 0

DELTA = (-1)^2-(-1*4*(1/3))

DELTA = 7/3

DELTA > 0

k = ((7/3)^(1/2)+1)/(2*(1/3)) or k = (1-(7/3)^(1/2))/(2*(1/3))

k = 3/2*((7/3)^(1/2)+1) or k = 3/2*(1-(7/3)^(1/2))

k in { 3/2*(1-(7/3)^(1/2)), 3/2*((7/3)^(1/2)+1)} 

k in { 3/2*(1-(7/3)^(1/2)), 3/2*((7/3)^(1/2)+1) }