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1/3k=1/2k
We move all terms to the left:
1/3k-(1/2k)=0
Domain of the equation: 3k!=0
k!=0/3
k!=0
k∈R
Domain of the equation: 2k)!=0We add all the numbers together, and all the variables
k!=0/1
k!=0
k∈R
1/3k-(+1/2k)=0
We get rid of parentheses
1/3k-1/2k=0
We calculate fractions
2k/6k^2+(-3k)/6k^2=0
We multiply all the terms by the denominator
2k+(-3k)=0
We get rid of parentheses
2k-3k=0
We add all the numbers together, and all the variables
-k=0
k=0/-1
k=0
Równanie nie ma rozwiązania
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