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1/3m+4=5/6m+2
We move all terms to the left:
1/3m+4-(5/6m+2)=0
Domain of the equation: 3m!=0
m!=0/3
m!=0
m∈R
Domain of the equation: 6m+2)!=0We get rid of parentheses
m∈R
1/3m-5/6m-2+4=0
We calculate fractions
6m/18m^2+(-15m)/18m^2-2+4=0
We add all the numbers together, and all the variables
6m/18m^2+(-15m)/18m^2+2=0
We multiply all the terms by the denominator
6m+(-15m)+2*18m^2=0
Wy multiply elements
36m^2+6m+(-15m)=0
We get rid of parentheses
36m^2+6m-15m=0
We add all the numbers together, and all the variables
36m^2-9m=0
a = 36; b = -9; c = 0;
Δ = b2-4ac
Δ = -92-4·36·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-9}{2*36}=\frac{0}{72} =0 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+9}{2*36}=\frac{18}{72} =1/4 $
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