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1/3m=5m+13
We move all terms to the left:
1/3m-(5m+13)=0
Domain of the equation: 3m!=0We get rid of parentheses
m!=0/3
m!=0
m∈R
1/3m-5m-13=0
We multiply all the terms by the denominator
-5m*3m-13*3m+1=0
Wy multiply elements
-15m^2-39m+1=0
a = -15; b = -39; c = +1;
Δ = b2-4ac
Δ = -392-4·(-15)·1
Δ = 1581
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-39)-\sqrt{1581}}{2*-15}=\frac{39-\sqrt{1581}}{-30} $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-39)+\sqrt{1581}}{2*-15}=\frac{39+\sqrt{1581}}{-30} $
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