1/3n-7=5/3(n+(-5)

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Solution for 1/3n-7=5/3(n+(-5) equation: 



1/3n-7=5/3(n+(-5)

We move all terms to the left:

1/3n-7-(5/3(n+(-5))=0



Domain of the equation: 3n!=0

n!=0/3

n!=0

n∈R





Domain of the equation: 3(n+(-5))-7!=0

We move all terms containing n to the left, all other terms to the right

3(n+(-5))!=7

n∈R



We calculate fractions


(3n(n-7)/(9n^2(n-7)+(-(5*3n)/(9n^2(n-7)=0



We calculate terms in parentheses: +(3n(n-7)/(9n^2(n-7)+(-(5*3n)/(9n^2(n-7), so:

3n(n-7)/(9n^2(n-7)+(-(5*3n)/(9n^2(n-7

We can not solve this equation

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