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1/3n=n-22
We move all terms to the left:
1/3n-(n-22)=0
Domain of the equation: 3n!=0We get rid of parentheses
n!=0/3
n!=0
n∈R
1/3n-n+22=0
We multiply all the terms by the denominator
-n*3n+22*3n+1=0
Wy multiply elements
-3n^2+66n+1=0
a = -3; b = 66; c = +1;
Δ = b2-4ac
Δ = 662-4·(-3)·1
Δ = 4368
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4368}=\sqrt{16*273}=\sqrt{16}*\sqrt{273}=4\sqrt{273}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(66)-4\sqrt{273}}{2*-3}=\frac{-66-4\sqrt{273}}{-6} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(66)+4\sqrt{273}}{2*-3}=\frac{-66+4\sqrt{273}}{-6} $
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