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1/3p+1/2p-10=0
Domain of the equation: 3p!=0
p!=0/3
p!=0
p∈R
Domain of the equation: 2p!=0We calculate fractions
p!=0/2
p!=0
p∈R
2p/6p^2+3p/6p^2-10=0
We multiply all the terms by the denominator
2p+3p-10*6p^2=0
We add all the numbers together, and all the variables
5p-10*6p^2=0
Wy multiply elements
-60p^2+5p=0
a = -60; b = 5; c = 0;
Δ = b2-4ac
Δ = 52-4·(-60)·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-5}{2*-60}=\frac{-10}{-120} =1/12 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+5}{2*-60}=\frac{0}{-120} =0 $
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