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1/3p-5=1/4p
We move all terms to the left:
1/3p-5-(1/4p)=0
Domain of the equation: 3p!=0
p!=0/3
p!=0
p∈R
Domain of the equation: 4p)!=0We add all the numbers together, and all the variables
p!=0/1
p!=0
p∈R
1/3p-(+1/4p)-5=0
We get rid of parentheses
1/3p-1/4p-5=0
We calculate fractions
4p/12p^2+(-3p)/12p^2-5=0
We multiply all the terms by the denominator
4p+(-3p)-5*12p^2=0
Wy multiply elements
-60p^2+4p+(-3p)=0
We get rid of parentheses
-60p^2+4p-3p=0
We add all the numbers together, and all the variables
-60p^2+p=0
a = -60; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·(-60)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*-60}=\frac{-2}{-120} =1/60 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*-60}=\frac{0}{-120} =0 $
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