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1/3p=4p
We move all terms to the left:
1/3p-(4p)=0
Domain of the equation: 3p!=0We add all the numbers together, and all the variables
p!=0/3
p!=0
p∈R
-4p+1/3p=0
We multiply all the terms by the denominator
-4p*3p+1=0
Wy multiply elements
-12p^2+1=0
a = -12; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·(-12)·1
Δ = 48
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{48}=\sqrt{16*3}=\sqrt{16}*\sqrt{3}=4\sqrt{3}$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{3}}{2*-12}=\frac{0-4\sqrt{3}}{-24} =-\frac{4\sqrt{3}}{-24} =-\frac{\sqrt{3}}{-6} $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{3}}{2*-12}=\frac{0+4\sqrt{3}}{-24} =\frac{4\sqrt{3}}{-24} =\frac{\sqrt{3}}{-6} $
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