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1/3t-(-6)=11
We move all terms to the left:
1/3t-(-6)-(11)=0
Domain of the equation: 3t!=0determiningTheFunctionDomain 1/3t-11-(-6)=0
t!=0/3
t!=0
t∈R
We add all the numbers together, and all the variables
1/3t-5=0
We multiply all the terms by the denominator
-5*3t+1=0
Wy multiply elements
-15t+1=0
We move all terms containing t to the left, all other terms to the right
-15t=-1
t=-1/-15
t=1/15
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