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1/3t=t-145
We move all terms to the left:
1/3t-(t-145)=0
Domain of the equation: 3t!=0We get rid of parentheses
t!=0/3
t!=0
t∈R
1/3t-t+145=0
We multiply all the terms by the denominator
-t*3t+145*3t+1=0
Wy multiply elements
-3t^2+435t+1=0
a = -3; b = 435; c = +1;
Δ = b2-4ac
Δ = 4352-4·(-3)·1
Δ = 189237
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(435)-\sqrt{189237}}{2*-3}=\frac{-435-\sqrt{189237}}{-6} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(435)+\sqrt{189237}}{2*-3}=\frac{-435+\sqrt{189237}}{-6} $
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