1/3w+w=20

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Solution for 1/3w+w=20 equation:



1/3w+w=20
We move all terms to the left:
1/3w+w-(20)=0
Domain of the equation: 3w!=0
w!=0/3
w!=0
w∈R
We add all the numbers together, and all the variables
w+1/3w-20=0
We multiply all the terms by the denominator
w*3w-20*3w+1=0
Wy multiply elements
3w^2-60w+1=0
a = 3; b = -60; c = +1;
Δ = b2-4ac
Δ = -602-4·3·1
Δ = 3588
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{3588}=\sqrt{4*897}=\sqrt{4}*\sqrt{897}=2\sqrt{897}$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-2\sqrt{897}}{2*3}=\frac{60-2\sqrt{897}}{6} $
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+2\sqrt{897}}{2*3}=\frac{60+2\sqrt{897}}{6} $

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