1/3x(6x-15)=1/2x(10x-4)

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Solution for 1/3x(6x-15)=1/2x(10x-4) equation: 



1/3x(6x-15)=1/2x(10x-4)

We move all terms to the left:

1/3x(6x-15)-(1/2x(10x-4))=0



Domain of the equation: 3x(6x-15)!=0

x∈R





Domain of the equation: 2x(10x-4))!=0

x∈R



We calculate fractions


(2x1/(3x(6x-15)*2x(10x-4)))+(-3x6/(3x(6x-15)*2x(10x-4)))=0



We calculate terms in parentheses: +(2x1/(3x(6x-15)*2x(10x-4))), so:

2x1/(3x(6x-15)*2x(10x-4))

We multiply all the terms by the denominator


2x1

We add all the numbers together, and all the variables

2x

Back to the equation:

+(2x)





We calculate terms in parentheses: +(-3x6/(3x(6x-15)*2x(10x-4))), so:

-3x6/(3x(6x-15)*2x(10x-4))

We multiply all the terms by the denominator


-3x6

We add all the numbers together, and all the variables

-3x^6

We do not support expression: x^6

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