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1/3x+1/5=-1(3/4x-3)
We move all terms to the left:
1/3x+1/5-(-1(3/4x-3))=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 4x-3))!=0We calculate fractions
x∈R
(-(-1(3*3x*5)/12x^2+48x^2/12x^2+4x/12x^2=0
We can not solve this equation
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