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1/3x+1/5=-2(5/6x+3)
We move all terms to the left:
1/3x+1/5-(-2(5/6x+3))=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 6x+3))!=0We calculate fractions
x∈R
(-(-2(5*3x*5)/18x^2+108x^2/18x^2+6x/18x^2=0
We can not solve this equation
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