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1/3x+1/5=3(2/3x-5)
We move all terms to the left:
1/3x+1/5-(3(2/3x-5))=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 3x-5))!=0We calculate fractions
x∈R
(-(3(2*3x*5)/9x^2+27x^2/9x^2+3x/9x^2=0
We can not solve this equation
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