1/3x+1/5=7/6(-7x-3)

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Solution for 1/3x+1/5=7/6(-7x-3) equation: 



1/3x+1/5=7/6(-7x-3)

We move all terms to the left:

1/3x+1/5-(7/6(-7x-3))=0



Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R





Domain of the equation: 6(-7x-3))!=0

x∈R



We calculate fractions


(30x(-)/(90x^2(-)+(-(7*3x*5)/(90x^2(-)+108x^2/(90x^2(-)=0



We calculate terms in parentheses: +(30x(-)/(90x^2(-)+(-(7*3x*5)/(90x^2(-)+108x^2/(90x^2(-), so:

30x(-)/(90x^2(-)+(-(7*3x*5)/(90x^2(-)+108x^2/(90x^2(-

We can not solve this equation

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