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1/3x+1/5x=1
We move all terms to the left:
1/3x+1/5x-(1)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 5x!=0We calculate fractions
x!=0/5
x!=0
x∈R
5x/15x^2+3x/15x^2-1=0
We multiply all the terms by the denominator
5x+3x-1*15x^2=0
We add all the numbers together, and all the variables
8x-1*15x^2=0
Wy multiply elements
-15x^2+8x=0
a = -15; b = 8; c = 0;
Δ = b2-4ac
Δ = 82-4·(-15)·0
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-8}{2*-15}=\frac{-16}{-30} =8/15 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+8}{2*-15}=\frac{0}{-30} =0 $
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