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1/3x+10=16
We move all terms to the left:
1/3x+10-(16)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
1/3x-6=0
We multiply all the terms by the denominator
-6*3x+1=0
Wy multiply elements
-18x+1=0
We move all terms containing x to the left, all other terms to the right
-18x=-1
x=-1/-18
x=1/18
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