1/3x+10=2x-5

Solution for 1/3x+10=2x-5 equation:

1/3x+10=2x-5

We move all terms to the left:

1/3x+10-(2x-5)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R


We get rid of parentheses

1/3x-2x+5+10=0

We multiply all the terms by the denominator


-2x*3x+5*3x+10*3x+1=0

Wy multiply elements

-6x^2+15x+30x+1=0

We add all the numbers together, and all the variables

-6x^2+45x+1=0

a = -6; b = 45; c = +1;
Δ = b2-4ac
Δ = 452-4·(-6)·1
Δ = 2049
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-\sqrt{2049}}{2*-6}=\frac{-45-\sqrt{2049}}{-12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+\sqrt{2049}}{2*-6}=\frac{-45+\sqrt{2049}}{-12}
$