1/3x+112=x

Solution for 1/3x+112=x equation:

1/3x+112=x

We move all terms to the left:

1/3x+112-(x)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R


We add all the numbers together, and all the variables

-1x+1/3x+112=0

We multiply all the terms by the denominator


-1x*3x+112*3x+1=0

Wy multiply elements

-3x^2+336x+1=0

a = -3; b = 336; c = +1;
Δ = b2-4ac
Δ = 3362-4·(-3)·1
Δ = 112908
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{112908}=\sqrt{37636*3}=\sqrt{37636}*\sqrt{3}=194\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(336)-194\sqrt{3}}{2*-3}=\frac{-336-194\sqrt{3}}{-6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(336)+194\sqrt{3}}{2*-3}=\frac{-336+194\sqrt{3}}{-6}
$