1/3x+12=1/2(x+12)

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Solution for 1/3x+12=1/2(x+12) equation: 



1/3x+12=1/2(x+12)

We move all terms to the left:

1/3x+12-(1/2(x+12))=0



Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R





Domain of the equation: 2(x+12))!=0

x∈R



We calculate fractions


(2xx/(6x^2x+(-(1*3x)/(6x^2x+12=0

We can not solve this equation

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