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1/3x+12=1/2(x+12)
We move all terms to the left:
1/3x+12-(1/2(x+12))=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 2(x+12))!=0We calculate fractions
x∈R
(2xx/(6x^2x+(-(1*3x)/(6x^2x+12=0
We can not solve this equation
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