1/3x+12=5/6x+28

Solution for 1/3x+12=5/6x+28 equation:

1/3x+12=5/6x+28

We move all terms to the left:

1/3x+12-(5/6x+28)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R



Domain of the equation: 6x+28)!=0

x∈R


We get rid of parentheses

1/3x-5/6x-28+12=0

We calculate fractions


6x/18x^2+(-15x)/18x^2-28+12=0

We add all the numbers together, and all the variables

6x/18x^2+(-15x)/18x^2-16=0

We multiply all the terms by the denominator


6x+(-15x)-16*18x^2=0

Wy multiply elements

-288x^2+6x+(-15x)=0

We get rid of parentheses

-288x^2+6x-15x=0

We add all the numbers together, and all the variables

-288x^2-9x=0

a = -288; b = -9; c = 0;
Δ = b2-4ac
Δ = -92-4·(-288)·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-9}{2*-288}=\frac{0}{-576}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+9}{2*-288}=\frac{18}{-576}
=-1/32
$