1/3x+12=x2-3

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Solution for 1/3x+12=x2-3 equation: 



1/3x+12=x2-3

We move all terms to the left:

1/3x+12-(x2-3)=0



Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R



We add all the numbers together, and all the variables

-(+x^2-3)+1/3x+12=0

We get rid of parentheses

-x^2+1/3x+3+12=0

We multiply all the terms by the denominator


-x^2*3x+3*3x+12*3x+1=0

Wy multiply elements

-3x^3+9x+36x+1=0

We do not support expression: x^3

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