1/3x+16=41

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Solution for 1/3x+16=41 equation:



1/3x+16=41
We move all terms to the left:
1/3x+16-(41)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
We add all the numbers together, and all the variables
1/3x-25=0
We multiply all the terms by the denominator
-25*3x+1=0
Wy multiply elements
-75x+1=0
We move all terms containing x to the left, all other terms to the right
-75x=-1
x=-1/-75
x=1/75

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