1/3x+1=1/6(2x+3

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Solution for 1/3x+1=1/6(2x+3 equation: 



1/3x+1=1/6(2x+3

We move all terms to the left:

1/3x+1-(1/6(2x+3)=0



Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R





Domain of the equation: 6(2x+3)+1!=0

We move all terms containing x to the left, all other terms to the right

6(2x+3)!=-1

x∈R



We calculate fractions


(6x(2+1)/(18x^2(2+1)+(-(1*3x)/(18x^2(2+1)=0



We calculate terms in parentheses: +(6x(2+1)/(18x^2(2+1)+(-(1*3x)/(18x^2(2+1), so:

6x(2+1)/(18x^2(2+1)+(-(1*3x)/(18x^2(2+1

We can not solve this equation

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