1/3x+1=16(2x+3)

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Solution for 1/3x+1=16(2x+3) equation: 



1/3x+1=16(2x+3)

We move all terms to the left:

1/3x+1-(16(2x+3))=0



Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R



We multiply all the terms by the denominator


-((16(2x+3)))*3x+1*3x+1=0

Wy multiply elements

-((16(2x+3)))*3x+3x+1=0

We add all the numbers together, and all the variables

3x-((16(2x+3)))*3x+1=0

We move all terms containing x to the left, all other terms to the right

3x-((16(2x+3)))*3x=-1

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