1/3x+1=4-1/6x

Solution for 1/3x+1=4-1/6x equation:

1/3x+1=4-1/6x

We move all terms to the left:

1/3x+1-(4-1/6x)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R



Domain of the equation: 6x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

1/3x-(-1/6x+4)+1=0

We get rid of parentheses

1/3x+1/6x-4+1=0

We calculate fractions


6x/18x^2+3x/18x^2-4+1=0

We add all the numbers together, and all the variables

6x/18x^2+3x/18x^2-3=0

We multiply all the terms by the denominator


6x+3x-3*18x^2=0

We add all the numbers together, and all the variables

9x-3*18x^2=0

Wy multiply elements

-54x^2+9x=0

a = -54; b = 9; c = 0;
Δ = b2-4ac
Δ = 92-4·(-54)·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-9}{2*-54}=\frac{-18}{-108}
=1/6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+9}{2*-54}=\frac{0}{-108}
=0
$