1/3x+1=5/6x-5

Solution for 1/3x+1=5/6x-5 equation:

1/3x+1=5/6x-5

We move all terms to the left:

1/3x+1-(5/6x-5)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R



Domain of the equation: 6x-5)!=0

x∈R


We get rid of parentheses

1/3x-5/6x+5+1=0

We calculate fractions


6x/18x^2+(-15x)/18x^2+5+1=0

We add all the numbers together, and all the variables

6x/18x^2+(-15x)/18x^2+6=0

We multiply all the terms by the denominator


6x+(-15x)+6*18x^2=0

Wy multiply elements

108x^2+6x+(-15x)=0

We get rid of parentheses

108x^2+6x-15x=0

We add all the numbers together, and all the variables

108x^2-9x=0

a = 108; b = -9; c = 0;
Δ = b2-4ac
Δ = -92-4·108·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-9}{2*108}=\frac{0}{216}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+9}{2*108}=\frac{18}{216}
=1/12
$