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1/3x+2/5=2/3-x
We move all terms to the left:
1/3x+2/5-(2/3-x)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 3-x)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
-x)!=-3
x!=-3/1
x!=-3
x∈R
1/3x-(-1x+2/3)+2/5=0
We get rid of parentheses
1/3x+1x-2/3+2/5=0
We calculate fractions
There is no solution for this equation
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