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1/3x+2/5x-1/2(x+3)=1/10
We move all terms to the left:
1/3x+2/5x-1/2(x+3)-(1/10)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 2(x+3)!=0We add all the numbers together, and all the variables
x∈R
1/3x+2/5x-1/2(x+3)-(+1/10)=0
We get rid of parentheses
1/3x+2/5x-1/2(x+3)-1/10=0
We calculate fractions
We do not support expression: x^3
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