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1/3x+2/5x=253
We move all terms to the left:
1/3x+2/5x-(253)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 5x!=0We calculate fractions
x!=0/5
x!=0
x∈R
5x/15x^2+6x/15x^2-253=0
We multiply all the terms by the denominator
5x+6x-253*15x^2=0
We add all the numbers together, and all the variables
11x-253*15x^2=0
Wy multiply elements
-3795x^2+11x=0
a = -3795; b = 11; c = 0;
Δ = b2-4ac
Δ = 112-4·(-3795)·0
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{121}=11$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-11}{2*-3795}=\frac{-22}{-7590} =1/345 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+11}{2*-3795}=\frac{0}{-7590} =0 $
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