1/3x+20=2/5x-2

Solution for 1/3x+20=2/5x-2 equation:

1/3x+20=2/5x-2

We move all terms to the left:

1/3x+20-(2/5x-2)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R



Domain of the equation: 5x-2)!=0

x∈R


We get rid of parentheses

1/3x-2/5x+2+20=0

We calculate fractions


5x/15x^2+(-6x)/15x^2+2+20=0

We add all the numbers together, and all the variables

5x/15x^2+(-6x)/15x^2+22=0

We multiply all the terms by the denominator


5x+(-6x)+22*15x^2=0

Wy multiply elements

330x^2+5x+(-6x)=0

We get rid of parentheses

330x^2+5x-6x=0

We add all the numbers together, and all the variables

330x^2-1x=0

a = 330; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·330·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*330}=\frac{0}{660}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*330}=\frac{2}{660}
=1/330
$