1/3x+26=7/3x+12

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Solution for 1/3x+26=7/3x+12 equation: 



1/3x+26=7/3x+12

We move all terms to the left:

1/3x+26-(7/3x+12)=0



Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R





Domain of the equation: 3x+12)!=0

x∈R



We get rid of parentheses

1/3x-7/3x-12+26=0

We multiply all the terms by the denominator


-12*3x+26*3x+1-7=0

We add all the numbers together, and all the variables

-12*3x+26*3x-6=0

Wy multiply elements

-36x+78x-6=0

We add all the numbers together, and all the variables

42x-6=0

We move all terms containing x to the left, all other terms to the right

42x=6

x=6/42

x=1/7

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