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1/3x+2=1/2x=4/3
We move all terms to the left:
1/3x+2-(1/2x)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
1/3x-(+1/2x)+2=0
We get rid of parentheses
1/3x-1/2x+2=0
We calculate fractions
2x/6x^2+(-3x)/6x^2+2=0
We multiply all the terms by the denominator
2x+(-3x)+2*6x^2=0
Wy multiply elements
12x^2+2x+(-3x)=0
We get rid of parentheses
12x^2+2x-3x=0
We add all the numbers together, and all the variables
12x^2-1x=0
a = 12; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·12·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*12}=\frac{0}{24} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*12}=\frac{2}{24} =1/12 $
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