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1/3x+2=2/x-1
We move all terms to the left:
1/3x+2-(2/x-1)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: x-1)!=0We get rid of parentheses
x∈R
1/3x-2/x+1+2=0
We calculate fractions
x/3x^2+(-6x)/3x^2+1+2=0
We add all the numbers together, and all the variables
x/3x^2+(-6x)/3x^2+3=0
We multiply all the terms by the denominator
x+(-6x)+3*3x^2=0
Wy multiply elements
9x^2+x+(-6x)=0
We get rid of parentheses
9x^2+x-6x=0
We add all the numbers together, and all the variables
9x^2-5x=0
a = 9; b = -5; c = 0;
Δ = b2-4ac
Δ = -52-4·9·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-5}{2*9}=\frac{0}{18} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+5}{2*9}=\frac{10}{18} =5/9 $
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