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1/3x+2=2x-13
We move all terms to the left:
1/3x+2-(2x-13)=0
Domain of the equation: 3x!=0We get rid of parentheses
x!=0/3
x!=0
x∈R
1/3x-2x+13+2=0
We multiply all the terms by the denominator
-2x*3x+13*3x+2*3x+1=0
Wy multiply elements
-6x^2+39x+6x+1=0
We add all the numbers together, and all the variables
-6x^2+45x+1=0
a = -6; b = 45; c = +1;
Δ = b2-4ac
Δ = 452-4·(-6)·1
Δ = 2049
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-\sqrt{2049}}{2*-6}=\frac{-45-\sqrt{2049}}{-12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+\sqrt{2049}}{2*-6}=\frac{-45+\sqrt{2049}}{-12} $
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