1/3x+2=2x-4

Solution for 1/3x+2=2x-4 equation:

1/3x+2=2x-4

We move all terms to the left:

1/3x+2-(2x-4)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R


We get rid of parentheses

1/3x-2x+4+2=0

We multiply all the terms by the denominator


-2x*3x+4*3x+2*3x+1=0

Wy multiply elements

-6x^2+12x+6x+1=0

We add all the numbers together, and all the variables

-6x^2+18x+1=0

a = -6; b = 18; c = +1;
Δ = b2-4ac
Δ = 182-4·(-6)·1
Δ = 348
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{348}=\sqrt{4*87}=\sqrt{4}*\sqrt{87}=2\sqrt{87}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-2\sqrt{87}}{2*-6}=\frac{-18-2\sqrt{87}}{-12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+2\sqrt{87}}{2*-6}=\frac{-18+2\sqrt{87}}{-12}
$