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1/3x+2=5/x-2
We move all terms to the left:
1/3x+2-(5/x-2)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: x-2)!=0We get rid of parentheses
x∈R
1/3x-5/x+2+2=0
We calculate fractions
x/3x^2+(-15x)/3x^2+2+2=0
We add all the numbers together, and all the variables
x/3x^2+(-15x)/3x^2+4=0
We multiply all the terms by the denominator
x+(-15x)+4*3x^2=0
Wy multiply elements
12x^2+x+(-15x)=0
We get rid of parentheses
12x^2+x-15x=0
We add all the numbers together, and all the variables
12x^2-14x=0
a = 12; b = -14; c = 0;
Δ = b2-4ac
Δ = -142-4·12·0
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{196}=14$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-14}{2*12}=\frac{0}{24} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+14}{2*12}=\frac{28}{24} =1+1/6 $
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