1/3x+2=7/3x+16

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Solution for 1/3x+2=7/3x+16 equation: 



1/3x+2=7/3x+16

We move all terms to the left:

1/3x+2-(7/3x+16)=0



Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R





Domain of the equation: 3x+16)!=0

x∈R



We get rid of parentheses

1/3x-7/3x-16+2=0

We multiply all the terms by the denominator


-16*3x+2*3x+1-7=0

We add all the numbers together, and all the variables

-16*3x+2*3x-6=0

Wy multiply elements

-48x+6x-6=0

We add all the numbers together, and all the variables

-42x-6=0

We move all terms containing x to the left, all other terms to the right

-42x=6

x=6/-42

x=-1/7

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