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1/3x+3+x=180
We move all terms to the left:
1/3x+3+x-(180)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
x+1/3x-177=0
We multiply all the terms by the denominator
x*3x-177*3x+1=0
Wy multiply elements
3x^2-531x+1=0
a = 3; b = -531; c = +1;
Δ = b2-4ac
Δ = -5312-4·3·1
Δ = 281949
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-531)-\sqrt{281949}}{2*3}=\frac{531-\sqrt{281949}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-531)+\sqrt{281949}}{2*3}=\frac{531+\sqrt{281949}}{6} $
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